Education degree does not equal strength, and it does not mean ability. Education degree just mean that you have this learning experience only. And the real ability is exercised in practice, it is not necessarily linked with the academic qualifications. Do not feel that you have no ability, and don't doubt yourself. When you choose to participate in the Oracle 1Z1-051 exam, it is necessary to pass it. If you are concerned about the test, however, you can choose ITCertKing's Oracle 1Z1-051 exam training materials. No matter how low your qualifications, you can easily understand the content of the training materials. And you can pass the exam successfully.
If you choose to sign up to participate in Oracle certification 1Z1-051 exams, you should choose a good learning material or training course to prepare for the examination right now. Because Oracle certification 1Z1-051 exam is difficult to pass. If you want to pass the exam, you must have a good preparation for the exam.
Working in IT industry, IT people most want to attend Oracle certification exam. As a widely recognized certification examination, Oracle certification exams are becoming more and more popular. Among them, Oracle 1Z1-051 certification test is the most important exam. Having 1Z1-051 certificate proves you have high skills. Owing to its importance, it is very difficult to pass Oracle 1Z1-051 exam successfully. Although to pass the exam is hard, you also don't need to worry about it. ITCertKing exam dumps will help you sail through 1Z1-051 test.
A lot of my friends from IT industry in order to pass Oracle certification 1Z1-051 exam have spend a lot of time and effort, but they did not choose training courses or online training, so passing the exam is so difficult for them and generally, the disposable passing rate is very low. Fortunately, ITCertKing can provide you the most reliable training tool for you. ITCertKing provide training resource that include simulation test software, simulation test, practice questions and answers about Oracle certification 1Z1-051 exam. We can provide the best and latest practice questions and answers of Oracle certification 1Z1-051 exam to meet your need.
Exam Code: 1Z1-051
Exam Name: Oracle (Oracle Database: SQL Fundamentals I)
One year free update, No help, Full refund!
Total Q&A: 254 Questions and Answers
Last Update: 2014-01-16
ITCertKing provide you the product with high quality and reliability. You can free download online part of ITCertKing's providing practice questions and answers about the Oracle certification 1Z1-051 exam as a try. After your trail I believe you will be very satisfied with our product. Such a good product which can help you pass the exam successfully, what are you waiting for? Please add it to your shopping cart.
1Z1-051 Free Demo Download: http://www.itcertking.com/1Z1-051_exam.html
NO.1 Which two statements are true regarding the USING and ON clauses in table joins? (Choose two.)
A. Both USING and ON clauses can be used for equijoins and nonequijoins.
B. A maximum of one pair of columns can be joined between two tables using the ON clause.
C. The ON clause can be used to join tables on columns that have different names but compatible data
types.
D. The WHERE clause can be used to apply additional conditions in SELECT statements containing the
ON or the USING clause.
Answer: CD
Oracle exam dumps 1Z1-051 1Z1-051
NO.2 Using the CUSTOMERS table, you need to generate a report that shows 50% of each credit
amount in each income level. The report should NOT show any repeated credit amounts in each income
level.
Which query would give the required result?
A. SELECT cust_income_level, DISTINCT cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
B. SELECT DISTINCT cust_income_level, DISTINCT cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
C. SELECT DISTINCT cust_income_level ' ' cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
D. SELECT cust_income_level ' ' cust_credit_limit * 0.50 AS "50% Credit Limit"
FROM customers;
Answer: C
Oracle 1Z1-051 1Z1-051 1Z1-051 test questions
NO.3 View the Exhibit and examine the data in the CUSTOMERS table.
Evaluate the following query:
SQL> SELECT cust_name AS "NAME", cust_credit_limit/2 AS MIDPOINT,MIDPOINT+100 AS "MAX
LOWER LIMIT"
FROM customers;
The above query produces an error on execution.
What is the reason for the error?
A. An alias cannot be used in an expression.
B. The a lias NAME should not be enclosed with in double quotation marks .
C. The MIDPOINT+100 expression gives an error because CUST_CREDIT_LIMIT contains NULL
values.
D. The a lias MIDPOINT should be enclosed with in double quotation marks for the
CUST_CREDIT_LIMIT/2 expression .
Answer: A
Oracle original questions 1Z1-051 1Z1-051 original questions 1Z1-051
NO.4 View the Exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)
A. listing of customers who do not have a credit limit and were born before 1980
B. finding the number of customers, in each city, whose marital status is 'married'
C. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
D. listing of those customers whose credit limit is the same as the credit limit of customers residing in the
city 'Tokyo'
E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of
all the customers
Answer: DE
Oracle demo 1Z1-051 1Z1-051 1Z1-051
NO.5 Which three statements are true regarding the data types in Oracle Database 10g/11g? (Choose
three.)
A. Only one LONG column can be used per table.
B. A TIMESTAMP data type column stores only time values with fractional seconds.
C. The BLOB data type column is used to store binary data in an operating system file.
D. The minimum column width that can be specified for a VARCHAR2 data type column is one.
E. The value for a CHAR data type column is blank-padded to the maximum defined column width.
Answer: ADE
Oracle exam 1Z1-051 1Z1-051 1Z1-051
NO.6 Examine the structure of the SHIPMENTS table:
name Null Type
PO_ID NOT NULL NUMBER(3)
PO_DATE NOT NULL DATE
SHIPMENT_DATE NOT NULL DATE
SHIPMENT_MODE VARCHAR2(30)
SHIPMENT_COST NUMBER(8,2)
You want to generate a report that displays the PO_ID and the penalty amount to be paid if the
SHIPMENT_DATE is later than one month from the PO_DATE. The penalty is $20 per day.
Evaluate the following two queries:
SQL> SELECT po_id, CASE
WHEN MONTHS_BETWEEN (shipment_date,po_date)>1 THEN
TO_CHAR((shipment_date - po_date) * 20) ELSE 'No Penalty' END PENALTY
FROM shipments;
SQL>SELECT po_id, DECODE
(MONTHS_BETWEEN (po_date,shipment_date)>1,
TO_CHAR((shipment_date - po_date) * 20), 'No Penalty') PENALTY
FROM shipments;
Which statement is true regarding the above commands?
A. Both execute successfully and give correct results.
B. Only the first query executes successfully but gives a wrong result.
C. Only the first query executes successfully and gives the correct result.
D. Only the second query executes successfully but gives a wrong result.
E. Only the second query executes successfully and gives the correct result.
Answer: C
Oracle braindump 1Z1-051 answers real questions 1Z1-051 1Z1-051 test questions 1Z1-051 1Z1-051 questions
NO.7 View the Exhibit; e xamine the structure of the PROMOTIONS table.
Each promotion has a duration of at least seven days .
Your manager has asked you to generate a report, which provides the weekly cost for each promotion
done to l date.
Which query would achieve the required result?
A. SELECT promo_name, promo_cost/promo_end_date-promo_begin_date/7
FROM promotions;
B. SELECT promo_name,(promo_cost/promo_end_date-promo_begin_date)/7
FROM promotions;
C. SELECT promo_name, promo_cost/(promo_end_date-promo_begin_date/7)
FROM promotions;
D. SELECT promo_name, promo_cost/((promo_end_date-promo_begin_date)/7)
FROM promotions;
Answer: D
Oracle questions 1Z1-051 1Z1-051 1Z1-051 test
NO.8 View the Exhibit to examine the description for the SALES table.
Which views can have all DML operations performed on it? (Choose all that apply.)
A. CREATE VIEW v3
AS SELECT * FROM SALES
WHERE cust_id = 2034
WITH CHECK OPTION;
B. CREATE VIEW v1
AS SELECT * FROM SALES
WHERE time_id <= SYSDATE - 2*365
WITH CHECK OPTION;
C. CREATE VIEW v2
AS SELECT prod_id, cust_id, time_id FROM SALES
WHERE time_id <= SYSDATE - 2*365
WITH CHECK OPTION;
D. CREATE VIEW v4
AS SELECT prod_id, cust_id, SUM(quantity_sold) FROM SALES
WHERE time_id <= SYSDATE - 2*365
GROUP BY prod_id, cust_id
WITH CHECK OPTION;
Answer: AB
Oracle exam prep 1Z1-051 1Z1-051 1Z1-051 pdf
NO.9 View the Exhibit and examine the structure of the PRODUCTS table.
You need to generate a report in the following format:
CATEGORIES
5MP Digital Photo Camera's category is Photo
Y Box's category is Electronics
Envoy Ambassador's category is Hardware
Which two queries would give the required output? (Choose two.)
A. SELECT prod_name q'''s category is ' prod_category CATEGORIES
FROM products;
B. SELECT prod_name q'['s ]'category is ' prod_category CATEGORIES
FROM products;
C. SELECT prod_name q'\'s\' ' category is ' prod_category CATEGORIES
FROM products;
D. SELECT prod_name q'<'s >' 'category is ' prod_category CATEGORIES
FROM products;
Answer: CD
Oracle exam dumps 1Z1-051 1Z1-051 1Z1-051 practice test 1Z1-051
NO.10 View the E xhibit and examine the data in the EMPLOYEES table.
You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:
SQL>SELECT ename ' joined on ' hiredate
', the total compensation paid is '
TO_CHAR(ROUND(ROUND(SYSDATE-hiredate)/365) * sal + comm)
"COMPENSATION UNTIL DATE"
FROM employees;
What is the outcome?
A. It generates an error because the alias is not valid.
B. It executes successfully and gives the correct output.
C. It executes successfully but does not give the correct output.
D. It generates an error because the usage of the ROUND function in the expression is not valid.
E. It generates an error because the concatenation operator can be used to combine only two items.
Answer: C
Oracle 1Z1-051 exam dumps 1Z1-051 original questions 1Z1-051 test questions 1Z1-051 answers real questions
NO.11 Examine the structure of the PROMOTIONS table:
name Null Type
PROMO_ID NOT NULL NUMBER(6)
PROMO_NAME NOT NULL VARCHAR2(30)
PROMO_CATEGORY NOT NULL VARCHAR2(30)
PROMO_COST NOT NULL NUMBER(10,2)
The management wants to see a report of unique promotion costs in each promotion category.
Which query would achieve the required result?
A. SELECT DISTINCT promo_cost, promo_category FROM promotions;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions;
C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
Answer: D
Oracle 1Z1-051 pdf 1Z1-051
NO.12 Evaluate the following query:
SQL> SELECT promo_name q'{'s start date was }' promo_begin_date
AS "Promotion Launches"
FROM promotions;
What would be the outcome of the above query?
A. It produces an error because flower braces have been used.
B. It produces an error because the data types are not matching.
C. It executes successfully and introduces an 's at the end of each promo_name in the output.
D. It executes successfully and displays the literal " {'s start date was } " for each row in the output.
Answer: C
Oracle 1Z1-051 1Z1-051
NO.13 You need to produce a report where each customer's credit limit has been incremented by $1000. In
the output, t he customer's last name should have the heading Name and the incremented credit limit
should be labeled New Credit Limit. The column headings should have only the first letter of each word in
uppercase .
Which statement would accomplish this requirement?
A. SELECT cust_last_name Name, cust_credit_limit + 1000
"New Credit Limit"
FROM customers;
B. SELECT cust_last_name AS Name, cust_credit_limit + 1000
AS New Credit Limit
FROM customers;
C. SELECT cust_last_name AS "Name", cust_credit_limit + 1000
AS "New Credit Limit"
FROM customers;
D. SELECT INITCAP(cust_last_name) "Name", cust_credit_limit + 1000
INITCAP("NEW CREDIT LIMIT")
FROM customers;
Answer: C
Oracle test answers 1Z1-051 1Z1-051
NO.14 Which two statements are true regarding single row functions? (Choose two.)
A. They a ccept only a single argument.
B. They c an be nested only to two levels.
C. Arguments can only be column values or constants.
D. They a lways return a single result row for every row of a queried table.
E. They c an return a data type value different from the one that is referenced.
Answer: DE
Oracle 1Z1-051 1Z1-051 answers real questions 1Z1-051 test 1Z1-051 exam prep
NO.15 You need to extract details of those products in the SALES table where the PROD_ID column
contains the string '_D123'.
Which WHERE clause could be used in the SELECT statement to get the required output?
A. WHERE prod_id LIKE '%_D123%' ESCAPE '_'
B. WHERE prod_id LIKE '%\_D123%' ESCAPE '\'
C. WHERE prod_id LIKE '%_D123%' ESCAPE '%_'
D. WHERE prod_id LIKE '%\_D123%' ESCAPE '\_'
Answer: B
Oracle 1Z1-051 1Z1-051 exam 1Z1-051 practice test
NO.16 View the Exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS, and TIMES
tables.
The PROD_ID column is the foreign key in the SALES table, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the
CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales(prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true regarding the above command?
A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the
column definition.
B. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified
columns would be passed to the new table.
C. The NEW_SALES table would not get created because the column names in the CREATE TABLE
command and the SELECT clause do not match.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the
specified columns would be passed to the new table.
Answer: B
Oracle test answers 1Z1-051 1Z1-051 1Z1-051
NO.17 Evaluate the following query:
SELECT INTERVAL '300' MONTH,
INTERVAL '54-2' YEAR TO MONTH,
INTERVAL '11:12:10.1234567' HOUR TO SECOND
FROM dual;
What is the correct output of the above query?
A. +25-00 , +54-02, +00 11:12:10.123457
B. +00-300, +54-02, +00 11:12:10.123457
C. +25-00 , +00-650, +00 11:12:10.123457
D. +00-300 , +00-650, +00 11:12:10.123457
Answer: A
Oracle 1Z1-051 1Z1-051 exam prep 1Z1-051 1Z1-051 braindump
NO.18 Which SQL statements would display the value 1890.55 as $1,890.55? (Choose three .)
A. SELECT TO_CHAR(1890.55,'$0G000D00')
FROM DUAL;
B. SELECT TO_CHAR(1890.55,'$9,999V99')
FROM DUAL;
C. SELECT TO_CHAR(1890.55,'$99,999D99')
FROM DUAL;
D. SELECT TO_CHAR(1890.55,'$99G999D00')
FROM DUAL;
E. SELECT TO_CHAR(1890.55,'$99G999D99')
FROM DUAL;
Answer: ADE
Oracle 1Z1-051 answers real questions 1Z1-051 exam dumps 1Z1-051 demo 1Z1-051
NO.19 Which statement is true regarding the INTERSECT operator?
A. It ignores NULL values.
B. Reversing the order of the intersected tables alters the result.
C. The names of columns in all SELECT statements must be identical.
D. The number of columns and data types must be identical for all SELECT statements in the query.
Answer: D
Oracle questions 1Z1-051 exam 1Z1-051 practice test 1Z1-051
NO.20 View the Exhibit and examine the structure of the PRODUCTS table.
All products have a list price.
You issue the following command to display the total price of each product after a discount of 25% and a
tax of 15% are applied on it. Freight charges of $100 have to be applied to all the products.
SQL>SELECT prod_name, prod_list_price -(prod_list_price*(25/100))
+(prod_list_price -(prod_list_price*(25/100))*(15/100))+100
AS "TOTAL PRICE"
FROM products;
What would be the outcome if all the parenthese s are removed from the above statement?
A. It produces a syntax error.
B. The result remains unchanged.
C. The total price value would be lower than the correct value.
D. The total price value would be higher than the correct value.
Answer: B
Oracle exam dumps 1Z1-051 1Z1-051 pdf
ITCertKing offer the latest C_TBW45_70 exam material and high-quality 70-465 pdf questions & answers. Our C_THR12_66 VCE testing engine and 200-001 study guide can help you pass the real exam. High-quality JN0-380 dumps training materials can 100% guarantee you pass the exam faster and easier. Pass the exam to obtain certification is so simple.
Article Link: http://www.itcertking.com/1Z1-051_exam.html